Koliko je molova glicerol-tristearata stupilo ureakciji ,ako je za potpunu hidrolizu utroseno 24g natrikum hodroksida?
CH2OOC(CH2)16CH3-CHOOC(CH2)16CH3-CH2OOC(CH2)16CH3+3NaOH----------->CH2OH-CHOH-CH2OH+3CH3(CH2)16COONa
n(NaOH)=m(NaOH)/Mr=24/40=0.6 mol
n(glicerol-tristearata):n(NaOH)=1:3
n(glicerol-tristearata)=n(NaOH)*1/3=0.6*1/3=0.2 mol
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CH2OOC(CH2)16CH3-CHOOC(CH2)16CH3-CH2OOC(CH2)16CH3+3NaOH----------->CH2OH-CHOH-CH2OH+3CH3(CH2)16COONa
n(NaOH)=m(NaOH)/Mr=24/40=0.6 mol
n(glicerol-tristearata):n(NaOH)=1:3
n(glicerol-tristearata)=n(NaOH)*1/3=0.6*1/3=0.2 mol