Koliko se molova natrijum-palmitata dobije baznom hidrolizom 0,2 mola glicerol-stearo-dipalmitata sa natijum-hidroksidom?
CH2OOC(CH2)16CH3-CHOOC(CH2)14CH3-CH2OOC(CH2)14CH3+3NaOH------------->2CH3(CH2)14COONa+CH3(CH2)16COONa+CH2OH-CHOH-CH2OH
n(glicerol-stearo-dialmitata)=0.2 mol
n(glicerol-stearo-dipamitat):n(natrijum-palmitat)=1:2
n(natrijum-palmitat)=n(glicerol-stearo-dipalmitat)*2/1=0.2*2/1=0.4 mol
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CH2OOC(CH2)16CH3-CHOOC(CH2)14CH3-CH2OOC(CH2)14CH3+3NaOH------------->2CH3(CH2)14COONa+CH3(CH2)16COONa+CH2OH-CHOH-CH2OH
n(glicerol-stearo-dialmitata)=0.2 mol
n(glicerol-stearo-dipamitat):n(natrijum-palmitat)=1:2
n(natrijum-palmitat)=n(glicerol-stearo-dipalmitat)*2/1=0.2*2/1=0.4 mol