Koliko se molekula vode adira na propen ako se iz tako dobijenog proizvoda u reakciji sa dovoljnom kolicinom natrijuma osobodi 56 cm3 gasa?
CH2=CH-CH3 + H2O = CH3-CH(OH)-CH3 (2-propanol)
CH3-CH(OH)-CH3 + Na = CH3-CH(ONa)-CH3 + 1/2H2
1mol 2-propanola : 0.5mol H2 = x : 0.0025mol H2 (0.056/22.4)
x=0.005mol 2-propanola
m(2-propanola)=0.005mol x 60 g/mol
m(2-propanola)=0.3 g
1mol H2O : 1mol 2-propanola = x mol H2O : 0.005mol 2-propanola
x=0.005mol H2O
N(H2O)=n(H2O)xNA
N(H2O)=0.005molx6.023x1023
N(H2O)=0.030115x1023
N(H2O)=3.0115x1021molekula
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CH2=CH-CH3 + H2O =
CH2=CH-CH3 + H2O = CH3-CH(OH)-CH3 (2-propanol)
CH3-CH(OH)-CH3 + Na = CH3-CH(ONa)-CH3 + 1/2H2
1mol 2-propanola : 0.5mol H2 = x : 0.0025mol H2 (0.056/22.4)
x=0.005mol 2-propanola
m(2-propanola)=0.005mol x 60 g/mol
m(2-propanola)=0.3 g
1mol H2O : 1mol 2-propanola = x mol H2O : 0.005mol 2-propanola
x=0.005mol H2O
N(H2O)=n(H2O)xNA
N(H2O)=0.005molx6.023x1023
N(H2O)=0.030115x1023
N(H2O)=3.0115x1021molekula