Izracunajte masu ciklopentantiola koja sadrzi istu kolicinu sumpora kao 24,4 g 1,4- butanditiola? Hvala unapred!
Mr(C4H10S2)=122g/mol, od toga 64g/mol sumpor.
24,4g: 122g/mol = m(S) : 64 g/mol
m(S)=(24,4g * 64g/mol) /122 g/mol=12,8g
Mr(C5H10S)=102g/mol, od toga 32g/mol sumpor
102g/mol :32 g/mol = x : 12,8g
x=1305,6g/32 =40,8g
HVALA!!! :D
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Mr(C4H10S2)=122g/mol, od
Mr(C4H10S2)=122g/mol, od toga 64g/mol sumpor.
24,4g: 122g/mol = m(S) : 64 g/mol
m(S)=(24,4g * 64g/mol) /122 g/mol=12,8g
Mr(C5H10S)=102g/mol, od toga 32g/mol sumpor
102g/mol :32 g/mol = x : 12,8g
x=1305,6g/32 =40,8g
HVALA!!! :D
HVALA!!! :D