Alkoholizom 0,3 mola acetil-hlorida, nastaje propil-acetat u prinosu od 75%. Koliko grama propil-acetata, kao glavnog proizvoda je dobijeno ? A. 22,95 B. 25,5 C. 76,5
CH3COCl+CH3CH2CH2OH-------------->CH3COOCH2CH2CH3+HCl
n(acetil-hlorida)=n(propil-acetata)=0.3 mol
m(propil-acetata)=n(propil-acetata)*Mr=102*0.3=30.6 g
m1(propil-acetata)=m(propil-acetata)*0.75=30.6*0.75=22.95 g
powered by Drupal
CH3COCl+CH3CH2CH2OH----------
CH3COCl+CH3CH2CH2OH-------------->CH3COOCH2CH2CH3+HCl
n(acetil-hlorida)=n(propil-acetata)=0.3 mol
m(propil-acetata)=n(propil-acetata)*Mr=102*0.3=30.6 g
m1(propil-acetata)=m(propil-acetata)*0.75=30.6*0.75=22.95 g