U kom masenom odnosu su reagovali propanal i mentanol ako je proizvod jedinjenje C5H12O2 o,1mol
CH3CH2CHO+2CH3OH------------->CH3CH2CH2CHOHOCH3+H2O
n(propanala)=n(C5H12O2)=0.1 mol
n(metanola)=2*n(C5H12O2)=0.2 mol
m(metanola)=n(metanola)*Mr=0.2*32=6.4 g
m(propanala)=n(propanala)*Mr=0.1*58=5.8 g
m(propanola):m(metanola)=5.8:6.4
powered by Drupal
Maseni odnos
CH3CH2CHO+2CH3OH------------->CH3CH2CH2CHOHOCH3+H2O
n(propanala)=n(C5H12O2)=0.1 mol
n(metanola)=2*n(C5H12O2)=0.2 mol
m(metanola)=n(metanola)*Mr=0.2*32=6.4 g
m(propanala)=n(propanala)*Mr=0.1*58=5.8 g
m(propanola):m(metanola)=5.8:6.4