Koliko se molova glicerol-trinitrata moze da dobije reakcijom 0,92g glicerola sa viskom nitratne kiseline ?
CH2OHCHOHCH2OH+3HNO3---------->CH2NO3CHNO3CH2NO3 +3H2O
n(glicerola)=m(glicerola)/Mr=0.92/92=0.01 mol
n(glicerol-trinitrata):n(glicerola)=1:1
n(glicerol-trinitrata)=n(glicerola)=0.01 mol
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CH2OHCHOHCH2OH+3HNO3---------->CH2NO3CHNO3CH2NO3 +3H2O
n(glicerola)=m(glicerola)/Mr=0.92/92=0.01 mol
n(glicerol-trinitrata):n(glicerola)=1:1
n(glicerol-trinitrata)=n(glicerola)=0.01 mol