Koliko grama NaOH treba dodati na 500g vode da bismo pripremili 0,1 molaran rastvor? Rešenje:2 g NaOH
c(NaOH)=0.1 mol/l
m(vode)=500 g a ro=1g/cm3
V=mr/ro=500/1=500 cm3
n(NaOH)=c(NaOH)*V=0.1*500*10(-3)=0.05 mol
m(NaOH)=n(NaOH)*Mr=0.05*40=2 g
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Rastvori
c(NaOH)=0.1 mol/l
m(vode)=500 g a ro=1g/cm3
V=mr/ro=500/1=500 cm3
n(NaOH)=c(NaOH)*V=0.1*500*10(-3)=0.05 mol
m(NaOH)=n(NaOH)*Mr=0.05*40=2 g