Koliko se molova natrijum-palmitata dobije baznom hidrolizom 0,2 mola glicerol-stearo-dipalmitata sa natrijum hidroksidom? Rejesenje je 0,4 mola. Hvala unapred.
CH2OOC(CH2)16CH3CHOOC(CH2)14CH3CH2OOC(CH2)14CH3+3NaOH------------>2CH3(CH2)14COONa+CH3(CH2)16COONa+CH2OHCHOHCH2OH
n(glicerol-stearo-dipalmitata):n(natrijum-palmitata)=1:2
n(natrijum-palmitata)=n(glicerol-stearo-dipalmitata)*2/1=0.2*2/1=0.4mol
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CH2OOC(CH2)16CH3CHOOC(CH2)14CH3CH2OOC(CH2)14CH3+3NaOH------------>2CH3(CH2)14COONa+CH3(CH2)16COONa+CH2OHCHOHCH2OH
n(glicerol-stearo-dipalmitata):n(natrijum-palmitata)=1:2
n(natrijum-palmitata)=n(glicerol-stearo-dipalmitata)*2/1=0.2*2/1=0.4mol