Izračunajte maseni udio u procentima rastvora koji je dobiven miješanjem 80g rastvora masenog udjela ω=0.05 i 120g rastvora masenog udjela ω=0.10 .
w1=0.05 mr1=80 g w2=0.10 mr2=120 g
ms1=w1*mr1=0.05*80=4 g a ms2=w2*mr2=0.10*120=12 g
msu=ms1+ms2=4+12=16 g
mru=mr1+mr2=80+120=200g pa je
wu=msu/mru=16/200=0.08=8%
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w1=0.05 mr1=80 g w2=0.10
w1=0.05 mr1=80 g w2=0.10 mr2=120 g
ms1=w1*mr1=0.05*80=4 g a ms2=w2*mr2=0.10*120=12 g
msu=ms1+ms2=4+12=16 g
mru=mr1+mr2=80+120=200g pa je
wu=msu/mru=16/200=0.08=8%