Koliko molova mlijecne kiseline nastane enzimskom hidrolizom 6,84 g mlijecnog secera,ako mu je molekulska masa 342?
C12H22O11+H2O-------------->4C3H6O3
m(C12H22O11)=6.84 g
n(C12H22O11)=m(C12H22O11)/Mr=6.84/342=0.02 mol
n(C3H6O3):n(C12H22O11)=4:1
n(C3H6O3)=4*n(C12H22O11)/1=4*0.02/1=0.08 mol
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organska hemija
C12H22O11+H2O-------------->4C3H6O3
m(C12H22O11)=6.84 g
n(C12H22O11)=m(C12H22O11)/Mr=6.84/342=0.02 mol
n(C3H6O3):n(C12H22O11)=4:1
n(C3H6O3)=4*n(C12H22O11)/1=4*0.02/1=0.08 mol