a)U koliko grama vode treba rastvoriti 100 g natrijum sulfata da bi se dobio 5% rastvor,a pod B) Koju masu vode u gramima treba ispariti iz 250g 10% rastvora da bi se dobio 60% rastvor? hvala unapres
a) m(Na2SO4)=100g w=5%
w=ms/mr
mr=ms/0.05=100/0.05=2000 g
m(vode)=mr-ms=2000-100=1900 g
b) w1=10% a w2=60%
w1=ms1/mr1 a w2=ms2/mr2
ms1=w1*mr1=0.10*250=25 g
ms1=ms2=25 g
mr2=ms2/w2=25/0.6=41.7 g
m(vode)=mr1-mr2=250-41.7=208.3 g
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Rastvor
a) m(Na2SO4)=100g w=5%
w=ms/mr
mr=ms/0.05=100/0.05=2000 g
m(vode)=mr-ms=2000-100=1900 g
b) w1=10% a w2=60%
w1=ms1/mr1 a w2=ms2/mr2
ms1=w1*mr1=0.10*250=25 g
ms1=ms2=25 g
mr2=ms2/w2=25/0.6=41.7 g
m(vode)=mr1-mr2=250-41.7=208.3 g