Koliko se molekula vode izdvoji pri nastanku 0,01 mola glicil-glicil alanina iz odgovarajucih aminokiselina?
2NH2CH2COOH+NH2CHCH3COOH------------->NH2CH2CONHCH2CONHCHCH3COOH+2H2O
n(vode):n(tripeptida)=2:1
n(vode)=n(tripeptida)*2/1=0.01*2/1=0.02 mol
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2NH2CH2COOH+NH2CHCH3COOH------------->NH2CH2CONHCH2CONHCHCH3COOH+2H2O
n(vode):n(tripeptida)=2:1
n(vode)=n(tripeptida)*2/1=0.01*2/1=0.02 mol