Koliko se molova vode izdvoji pri nastanku 0,2 moa tripeptida alanilglicilcisteina?
NH2CHCH3COOH+NH2CH2COOH+NH2CHCH2SHCOOH-------------->NH2CHCH3CONHCH2CONHCHCH2SHCOOH+2H2O
n(tripeptida):n(vode)=1:2
n(vode)=n(tripeptida)*2/1=2*0.2/1=0.4 mol
powered by Drupal
organska hemija
NH2CHCH3COOH+NH2CH2COOH+NH2CHCH2SHCOOH-------------->NH2CHCH3CONHCH2CONHCHCH2SHCOOH+2H2O
n(tripeptida):n(vode)=1:2
n(vode)=n(tripeptida)*2/1=2*0.2/1=0.4 mol