Koliko grama etanamida nastaje potpunom amonolizom 0,05 mola odgovarajuceg acil halogenida
CH3COCl+NH3----------->CH3CONH2+HCl
n(CH3COCl)=0.05 mol
n(CH3CONH2):n(CH3COCl)=1:1
n(CH3CONH2)=n(CH3COCl)=0.05 mol
m(CH3CONH2)=n*Mr=0.05*59=2.95 g
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zadatak sa prijemnog aminoliza acil halogenida
CH3COCl+NH3----------->CH3CONH2+HCl
n(CH3COCl)=0.05 mol
n(CH3CONH2):n(CH3COCl)=1:1
n(CH3CONH2)=n(CH3COCl)=0.05 mol
m(CH3CONH2)=n*Mr=0.05*59=2.95 g