Koliko je ml 38% hloridne kiseline HCl gustine 1,19 g/cm3 potrebno da se dobije 1L rastvora koncentracije 2 mol/L?
R:161,44ml
c=2 mol/l a V=1l
n(HCl)=c*V=2*1=2 mol
m(HCl)=n*Mr=2*36.5=73g
mr=ms/w=73/0.38=192.1g
V=mr/ro=192.1/1.19=161.44 ml
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Conc.
c=2 mol/l a V=1l
n(HCl)=c*V=2*1=2 mol
m(HCl)=n*Mr=2*36.5=73g
mr=ms/w=73/0.38=192.1g
V=mr/ro=192.1/1.19=161.44 ml