Potpunom saponifikacijom nekog ulja,a zatim dejstvom hlorovodonika,dobija se smesa stearinske i linolne kiseline.Koliko procenata linolne kiseline ima u smesi ako 2g ove smese adira 2,54g joda?Hvala unapred! :)
ulje(saponifikacija)+HCl------------>C17H35COOH+CH3(CH2)7CH=CHCH2CH=CH(CH2)4COOH
CH3(CH2)7CH=CHCH2CH=CH(CH2)4COOH+2J2---->CH3(CH2)7CHJCHJCH2CHJCHJ(CH2)4COOH
n(j2)=m/Mr=2.54/2540.01 mol pa je
n(linolne kiseline):n(J2)=1:2
n(linolne kiseline)=n(J2)*1/2=0.01*1/2=0.005 mol
m(linolne kiseline)=n*Mr=0.005*284=1.42g
w=ms/mr=1.42/2=71% linolne kiseline
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ulje(saponifikacija)+HCl------------>C17H35COOH+CH3(CH2)7CH=CHCH2CH=CH(CH2)4COOH
CH3(CH2)7CH=CHCH2CH=CH(CH2)4COOH+2J2---->CH3(CH2)7CHJCHJCH2CHJCHJ(CH2)4COOH
n(j2)=m/Mr=2.54/2540.01 mol pa je
n(linolne kiseline):n(J2)=1:2
n(linolne kiseline)=n(J2)*1/2=0.01*1/2=0.005 mol
m(linolne kiseline)=n*Mr=0.005*284=1.42g
w=ms/mr=1.42/2=71% linolne kiseline