Koliko se molova vode izdvoji pri nastajanju 0,5 mol tripeptida glicil-alanil-cisteina ?
CH2(NH2)COOH+CH3CH(NH2)COOH+SHCH2CH(NH2)COOH----------->
H2NCH2CONHCHCH3CONHCHCH2SHCOOH+2H2O
n(tripeptida):n(vode)=1:2
n(vode)=n(tripeptida)*2/1=2*0.5/1=1 mol
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Tripeptid glicil alanin-cistein
CH2(NH2)COOH+CH3CH(NH2)COOH+SHCH2CH(NH2)COOH----------->
H2NCH2CONHCHCH3CONHCHCH2SHCOOH+2H2O
n(tripeptida):n(vode)=1:2
n(vode)=n(tripeptida)*2/1=2*0.5/1=1 mol