Sistem apsorbuje iz okoline 50 KJ toplote i na racun te toplote vrsi rad od 50 KJ. Kolika je promena unutrasnje energije sistama u ovom procesu? Resenje je: 0 KJ ... Zna li neko postupak, koja se formula tu koristi??
Q=deltaU+A gde su: Q-primljena kolicina toplote; deltaU-promena unutrasnje energije; A-rad koji vrsi sistem
Ovde se odmah vidi resenje, ali moze i "preko formule": deltaU=Q-A=50kJ-50kJ=0
"A new scientific truth does not triumph by convincing opponents and making them see the light, but rather because its opponents eventually die, and a new generation grows up that is familiar with it"Max Planck
Q=deltaU+Agde su:
Q=deltaU+A
gde su: Q-primljena kolicina toplote; deltaU-promena unutrasnje energije; A-rad koji vrsi sistem
Ovde se odmah vidi resenje, ali moze i "preko formule":
deltaU=Q-A=50kJ-50kJ=0
"A new scientific truth does not triumph by convincing opponents and making them see the light, but rather because its opponents eventually die, and a new generation grows up that is familiar with it" Max Planck