Koliko gr. Zn ima u 15 gr. ZnCl2?
Mislim ja da to treba rijesiti pomocu formule n=m/M, ali nisam bas sigurna...
x grama cinka : 15 grama cink-hlorida = 65,5 g/mol(relativna atomska masa cinka) : 136,5 g/mol(relativna molekulska masa cink-hlorida)
X=7,2g Zn
powered by Drupal
x grama cinka : 15 grama
x grama cinka : 15 grama cink-hlorida = 65,5 g/mol(relativna atomska masa cinka) : 136,5 g/mol(relativna molekulska masa cink-hlorida)
X=7,2g Zn