koliko cm3 69,8 % HNO2, gustine 1,42 g/cm3 treba uzeti i razblaziti vodom, da bi se dobilo 800 cm3 rastvora koncentracije 0,5 mol/dm3?
w1(HNO2)=69.8%=0.698
ρ1(HNO2)=1.42g/cm3
V2=800 cm3
c2(HNO2)=0.5mol/dm3
c2=n/V
c2=m/M*V...m=c*M*V..m(HNO2)=0.5mol/dm3*47g/mol*0.8dm3=18.8g
w=ms/mr...mr=ms/w... mr=18.8g/0.698=26.93g
ρ=mr/V....V=mr/ρ... V=26.93g/1.42g/cm3=18.96cm3
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w1(HNO2)=69.8%=0.698 ρ1(HNO2
w1(HNO2)=69.8%=0.698
ρ1(HNO2)=1.42g/cm3
V2=800 cm3
c2(HNO2)=0.5mol/dm3
c2=n/V
c2=m/M*V...m=c*M*V..m(HNO2)=0.5mol/dm3*47g/mol*0.8dm3=18.8g
w=ms/mr...mr=ms/w... mr=18.8g/0.698=26.93g
ρ=mr/V....V=mr/ρ... V=26.93g/1.42g/cm3=18.96cm3