Na 5,6 g alkena P adira se 16 g broma. Katalitickom hidrogenizacijom alkena P nastaje zasiceni ugljovodnik R, koji u svom molekulu nema sekundarnih C-atoma. Alken P je....??
n(Br2)=16g/160g/mol=0.1mol
n(alken)=n(Br2)=0.1mol
M(alken)=5.6g/0.1mol=56g/mol
formula je:CnH2n, 12*n+1*2*n=14n
n=56/14=4
Alken je C4H8.
Posto alkan nema sekundarnih C atoma alken mora biti 2-metil-1-propen.
The goal of life is living in agreement with nature.
n(Br2)=16g/160g/mol=0.1mol n(
n(Br2)=16g/160g/mol=0.1mol
n(alken)=n(Br2)=0.1mol
M(alken)=5.6g/0.1mol=56g/mol
formula je:CnH2n, 12*n+1*2*n=14n
n=56/14=4
Alken je C4H8.
Posto alkan nema sekundarnih C atoma alken mora biti 2-metil-1-propen.
The goal of life is living in agreement with nature.