Koliko ce se potrositi grama vodonika za potpunu hidrogenizaciju 0.03 mola benzena?
C6H6+3H2--->C6H12 n(H2)=n(C6H6)*3=0.09mol m=0.09mol*2g/mol=0.18g
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C6H6+3H2--->C6H12 n(H2)=n(C6H
C6H6+3H2--->C6H12
n(H2)=n(C6H6)*3=0.09mol
m=0.09mol*2g/mol=0.18g