Treba mi pomoc oko sledeceg zadatka: 10ml zeludacnog soka tretirano je 0,1M NaOH i za neutralizaciju je potroseno 7,2ml. Koliki je pH zeludacnog soka? Hvala unapred!
c1V1=c2V2 c1=c2V2/V1 c1=7.2ml*0.1M/10ml=0.072mol/dm^3 [H+]=0.072mol/dm^3 pH=-log[H+]=1.143
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c1V1=c2V2 c1=c2V2/V1 c1=7.2ml
c1V1=c2V2
c1=c2V2/V1
c1=7.2ml*0.1M/10ml=0.072mol/dm^3
[H+]=0.072mol/dm^3
pH=-log[H+]=1.143