Koliko grama acetil-hlorida treba utrositi za dobijanje 6,12 g anhidrida sircetne kiseline u reakciji sa dovoljnom kolicinom natrijum-acetata?
CH3COCl + CH3COONa -> CH3COOCOCH3 + NaCl n(anhidrid0)=6.12/102 n=0.06mol n(acetil-hlorid):n(anhidrid)=1:1 m(acetil-hlorid)=0.06*78.5 m=4.71g
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CH3COCl + CH3COONa ->
CH3COCl + CH3COONa -> CH3COOCOCH3 + NaCl
n(anhidrid0)=6.12/102
n=0.06mol
n(acetil-hlorid):n(anhidrid)=1:1
m(acetil-hlorid)=0.06*78.5
m=4.71g