Koliko grama formaldehida moze da izdvoji 0,5 mola srebra iz amonijacnog rastvora srebro-nitrata? Resenje je 7,5...
HCHO+2[Ag(NH3)2]+ + 2OH - --->HCOOH+2Ag+4NH3+H2O n(HCHO):n(Ag)=1:2 n(HCHO)=0.25mol m(HCHO)=0.25mol*30g/mol=7.5g
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HCHO+2[Ag(NH3)2]+ + 2OH -
HCHO+2[Ag(NH3)2]+ + 2OH - --->HCOOH+2Ag+4NH3+H2O
n(HCHO):n(Ag)=1:2
n(HCHO)=0.25mol
m(HCHO)=0.25mol*30g/mol=7.5g