Rastvor sadrzi 1,2 g sircetne kiseline. izracunati Nd (disosovani molekuli) ako disosuje 2,5%. Hitno mi je. Hvala unapred. :)
n=1.2g/60g/mol=0.02mol nd=0.02mol*0.025=0.0005mol Nd=0.0005*6*10^23=3*10^20
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n=1.2g/60g/mol=0.02mol nd=0.0
n=1.2g/60g/mol=0.02mol
nd=0.02mol*0.025=0.0005mol
Nd=0.0005*6*10^23=3*10^20