Koliko se dobija grama vodonik-sulfida iz 3 g sumpora i 3 g vodonika? (S-32).
n(S)=3g/32g/mol=0.09375mol n(H2)=3g/2g/mol=1.5mol H2+S--->H2S reaguju u odnosu 1:1, pa ce ostati H2 u visku, radimo preko sumpora n(H2S)=n(S)=0.09375mol m(H2S)=0.09375mol*34g/mol=3.1875g
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n(S)=3g/32g/mol=0.09375mol n(
n(S)=3g/32g/mol=0.09375mol
n(H2)=3g/2g/mol=1.5mol
H2+S--->H2S
reaguju u odnosu 1:1, pa ce ostati H2 u visku, radimo preko sumpora
n(H2S)=n(S)=0.09375mol
m(H2S)=0.09375mol*34g/mol=3.1875g