Kolika je koncetracija vodonikovih jona (mmol/L) u rastvoru sirćetne kiseline koncentracije 0.01 mol/L, ako je stepen disocijacije 4.2%?
CH3COOH->H+ + CH3COO- C=0.01mol/l alfa=4.2%=0.042 (1-alfa~1) C(H+)=C*alfa C(H+)=0.01*0.042 C(H+)=0.00042mol/l=0.42mmol/L
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CH3COOH->H+ +
CH3COOH->H+ + CH3COO-
C=0.01mol/l
alfa=4.2%=0.042
(1-alfa~1)
C(H+)=C*alfa
C(H+)=0.01*0.042
C(H+)=0.00042mol/l=0.42mmol/L