Koliko se toplote oslobađa pri sagorevanju 4 grama kalcijuma? Delta r H na nultu (CaO) = 636,0 kj/mol, (Ca-40) ako moze sto pre, unapred zahvalna :*
Ca+1/2O2--->CaO n(Ca)=0.1mol n(Ca)=n(Ca0) deltaH=delta r H*n(Ca0) delta H=63.6kJ
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Ca+1/2O2--->CaO n(Ca)=0.1mol
Ca+1/2O2--->CaO
n(Ca)=0.1mol
n(Ca)=n(Ca0)
deltaH=delta r H*n(Ca0)
delta H=63.6kJ