Koliko je potrebno mililitara kalijum-nitrata koji u 1 L sadrzi 50, 5 g za pravljenje 100 mL rastvora koji u 1 L sadrzi 0,1 mol kalijum-nitrata?
n=V*C n=0.1l*0.1mol/l=0.01mol m=n*M m=0.01mol*101g/mol=1.01g V=m/gama V=1.01g/50.5g/l V=0.02l=20ml
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n=V*C n=0.1l*0.1mol/l=0.01mol
n=V*C
n=0.1l*0.1mol/l=0.01mol
m=n*M
m=0.01mol*101g/mol=1.01g
V=m/gama
V=1.01g/50.5g/l
V=0.02l=20ml